###
**How many terms are there in 20, 25, 30 . . . . . . 140?**

A. 22
B. 25
C. 23
D. 24
**Answer: Option B**

## Show Answer

Solution(By Apex Team)

$\begin{aligned}&\text{Number of terms,}\\
&=\frac{\left(\text{ last term }-1^{\text{st}}\text{ term }\right)}{\text{Common difference}}\text{ }+1\\
&=\frac{140-20}{5}+1\\
&=\frac{120}{5}+1\\
&=24+1\\
&=25\end{aligned}$

## Related Questions On Progressions

### How many terms are there in 20, 25, 30 . . . . . . 140?

A. 22B. 25

C. 23

D. 24

### Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.

A. 5B. 6

C. 4

D. 3

### Find the 15th term of the sequence 20, 15, 10 . . .

A. -45B. -55

C. -50

D. 0

### The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is

A. 600B. 765

C. 640

D. 680